快慢指针法

判断一个链表是否存在环

  • code
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/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if(head==null) return false;
if(head.next==null) return false;
if(head.next.next==null) return false;

ListNode slow=head;
ListNode fast=head;
while(fast!=null && fast.next!=null){
slow=slow.next;
fast=fast.next.next;
if(fast==slow){
return true;
}
}
return false;
}
}